1.

The apparent depth of ater in water in cylindrical water tank of diameter 2R cm is reducing at the rate of x cm//min when is being drined out a constant rate. The amount of water drained in cc//min is (n_1=refractive index of air, n_2=refractive index of water)

Answer»

`(xpiR^2n_1)/n_2`
`(xpiR^2n_1)/n_1`
`(2piRn_1)/n_2`
`piR^2x`

SOLUTION :`d_(APP)=d/((n_1//n_2))`
`:. d=n_2/n_1 d_(app)`
`-d/(DT) =n_2/n_1(-d/(dt) d_(app))=(n_2/n_1)X`
`(DV)/dt=A[-d/(dt)(d)]=(xpiR^2n_2)/n_1`


Discussion

No Comment Found

Related InterviewSolutions