1.

The applied input ac power to a half wave rectifier is 100 W. The dc output power obtained is 40W. Find the rectifier efficiency.

Answer»

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Solution :AC input POWER= 100 W, dc output power = 40 W.
`"RECTIFIER efficiency "=("dc power output")/("Input ac power")=(P_(dc))/(P_(ac))=(40)/(100)=0.4`
`therefore` PERCENTAGE efficiency of the half wave rectifier `= 40%`


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