The approxiamte standard enthalpies of formation of methanol and octane are determiend to be -1.5 kJ/mol and -10.9 kJ/mol respectively. The standard enthalpies of combustion of octane is denoted as `DeltaH("octane")` and that fo methanol as `DeltaH` (methanol). the correct statement is:A. `DeltaH` (octane) is more negative than `DeltaH` (methanol)B. `DeltaH`(octane) is less negative than `DeltaH` (methanol)C. `DeltaH` (octane) is equal to `DeltaH` (methanol)D. `DeltaH` (octane)`+DeltaH`(methanol)=0

The approxiamte standard enthalpies of formation of methanol and octan

1.	The approxiamte standard enthalpies of formation of methanol and octane are determiend to be -1.5 kJ/mol and -10.9 kJ/mol respectively. The standard enthalpies of combustion of octane is denoted as `DeltaH("octane")` and that fo methanol as `DeltaH` (methanol). the correct statement is:A. `DeltaH` (octane) is more negative than `DeltaH` (methanol)B. `DeltaH`(octane) is less negative than `DeltaH` (methanol)C. `DeltaH` (octane) is equal to `DeltaH` (methanol)D. `DeltaH` (octane)`+DeltaH`(methanol)=0
Answer» Correct Answer - A Heat of combustion of octane will be more negative than methanol because octane has greaterr number of carbon than methanol.

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