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The approximate formula expressing the formula of mutual inductance of two coaxial loops of the same redius `a` when their centers are separated by a distance `l` with `l gt gt a` isA. `(1)/(2) (mu_(0)pia^(4))/(l^(3))`B. `(1)/(2) (mu_(0)a^(4))/(l^(2))`C. `(mu_(0))/(4pi) (pia^(4))/(l^(2))`D. `(mu_(0))/(pi) (a^(4))/(l^(3))` |
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Answer» Correct Answer - A Let `I =` current in one loop. The magnetic field at the centre of the other co-axial loop at a distance `l` from the centre of the first loop is `B = (mu_(0))/(4pi) (2I pia^(2))/((a^(2) + l^(2))^(3//2))` where `p_(m) = I pia^(2)` = magnetic moment of the loop Flux through the other loop is `phi_(12) = Bpi a^(2)` `= (mu_(0))/(4pi) (2I pia^(2))/((a^(2) + l^(2))^(3//2)) pi a^(2)` or `M = (phi_(12))/(I) = (mu_(0))/(4pi) (2I pia^(4))/((a^(2) + l^(2))^(3//2))` `= (mu_(0) pia^(4))/(2(a^(2) + l^(2))^(3//2))= (mu_(0)pia^(4))/(2l^(3)) (alt lt l)` |
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