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The approximate value of `(1.0002)^3000`, isA. 1.6B. 1.4C. 1.8D. 1.2 |
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Answer» Correct Answer - a We have , ` (1 + x)^(n) cong1 + nx if x lt 1` `therefore (1 .0002)^(3000) cong1 + 3000 xx0.0002 = 1.6` |
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