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The approximate wavelength of a photon of energy `2.48 eV` isA. `500 Å`B. `5000 Å`C. `2000 Å`D. `1000 Å` |
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Answer» Correct Answer - B By using `E( eV) = (12375)/(lambda (Å))` `rArr lambda = (12375)/(2.48) = 4989.9 Å ~~ 5000 Å` |
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