The area of a kite is 6 times the length of its shortest diagonal minus 9 and its longest diagonal is 6 cm long. 1) Find the length of the shortest diagonal, 2) Find the area of the kite, 3) If the shortest diagonal is given as 3cm, find the length of the longest diagonal.

The area of a kite is 6 times the length of its shortest diagonal m

1.	The area of a kite is 6 times the length of its shortest diagonal minus 9 and its longest diagonal is 6 cm long. 1) Find the length of the shortest diagonal, 2) Find the area of the kite, 3) If the shortest diagonal is given as 3cm, find the length of the longest diagonal.
Answer» Area of kite =6a-9(where a=LENGTH of its SHORTEST DIAGONAL)cmwhere the longest diagonal =6cm1::Area of kite =(longest diagonal ×shortest diagonal )/2 6a-9 = (6×a)/2 2(6a-9) = 6a 12a-18 = 6a 12a-6a = 18 6a = 18 a = 18/6 a = 3 shortest diagonal length =3cm2:area of kite=6a-9 a = 3 Area= (6×3) -9 = 18-9 = 9area of kite=9cm (or)area of kite =longest diagonal ×shortest diagonal/2 = 6×3/2 =18/2 =9area of kite = 9cm3::if the shortest diagonal =3cmthen, area of kite = 9cm 9 =(a×3)/2(a=longest diagonal) 9×2=3a 18=3a 18/3= a a=6cmlongest diagonal length =3cm