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the area of a tight angled trinagle is 80 sq cm. one of the perpendicular sides is 20 cm long. what is the length of the other? |
Answer» AnswerPerpendicular = 20 cm and BASE = 7 Area = 1/2 × Base × Pripendicular 10 = 1/2 × Base × 20 therefore, Base = 1CM |
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