1.

the area of a tight angled trinagle is 80 sq cm. one of the perpendicular sides is 20 cm long. what is the length of the other?​

Answer»

Answer

Given that, AREA = 10 sq. CM.

Perpendicular = 20 cm and BASE = 7

Area = 1/2 × Base × Pripendicular

10 = 1/2 × Base × 20

therefore, Base = 1CM

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