Step-by-step explanation:

Given:-

The area of a trapezium is 352 cm² and the distance between its parallel SIDES is 16 cm. If one of the parallel sides is of length 25 cm.

To find:-

find the length of the other.

Solution:-

One of the parallel sides of a Trapezium is 25 cm

Let a=25 cm

Let the other Parallel side of the Trapezium= b cm

Distance between the two parallel sides=16 cm

h=16 cm

Area of a Trapezium=(1/2)h(a+b)=h(a+b)/2 sq.units

We have ,

a= 25 cm

b=b cm

h=16 cm

On Substituting these values in the formula

=>16(25+b)/2 sq.cm

=>8(25+b) sq.cm

=>200+8b sq.cm

Area of the Trapezium=8b+200 sq.cm

According to the given problem

Area of the Trapezium=352 cm²

=>8b+200=352

=>8b=352-200

=>8b=152

=>b=152/8

=>b=19

b=19 cm

Answer:-

The length of the other Parallel side of the Trapezium is 19 cm

Check:-

We have ,

a=25 cm

b=19 cm

h=16 cm

area of the Trapezium=h(a+b)/2 sq.units

=>16(25+19)/2 cm²

=>8(44) cm²

=>352 cm²

area of the Trapezium=352 cm²

Verified the relation .

Used formula :-

If "a" and "b" are the two parallel sides and "h" is the distance between them of the Trapezium then the area of the Trapezium is h(a+b)/2 sq.units