The area of a triangle is 48 cm square. The height of the triangle is

1.	The area of a triangle is 48 cm square. The height of the triangle is 6cm. Calculate the length of the base.
Answer» Given: Area of a triangle = 48 cm² Height of the triangle = 6 cm To Find: Length of the BASE = ?? Formula Used: $\boxed{\mathtt{Area\: of\:Triangle=\dfrac{1}{2}(B \times H)}}$ Solution: As we know, $\mathtt{Area_{(Triangle)}=\dfrac{1}{2}(B \times H)}$ Where, B = Base H = Height After substituting values, $48cm^2=\dfrac{1}{2}(B \times 6)$ After opening BRACKETS, we get: $48=\dfrac{1}{2}\times 6B$ After multiplying ½ with 6B, $48= 3B$ After transposing 3 from RHS to LHS and changing its sign, $\dfrac{48}{3}= B$ After DIVIDING 48 by 3, $16= B$ Hence, length of the base of the triangle is 16 cm.