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The area of a triangle with vertices A(3,0),B(7,0) and C(8,4) isA. 14sq unitsB. 28 sq unitsC. 8 sq unitsD. 6 sq units |
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Answer» Correct Answer - C Here, `(x_(1) = 3, y_(1) = 0), (x_(2) = 7, y_(2) = 0) "and" (x_(3) = 8, y_(3) = 4)` `therefore "area of "Delta ABC = (1)/(2) {x_(1) (y_(2)-y_(3)) +x_(2)(y_(3)-y_(1)) +x_(3)(y_(1) -y_(2))}` ` = (1)/(2) {3(0-4) + 7(4-0) + 8(0-0)} = (1)/(2){-12 +28 +0}` ` = ((1)/(2) xx 16) = 8` sq units. |
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