The area of any cyclic quadrilateral ABCD is given by `A^(2) = (s -a) (s-b) (s-c) (s-d)`, where `2s = a + b ++ c + d, a, b, c and d` are the sides of the quadrilateral Now consider a cyclic quadrilateral ABCD of area 1 sq. unit and answer the following question The minium perimeter of the quadrilateral isA. 4B. 2C. 1D. none of these

The area of any cyclic quadrilateral ABCD is given by `A^(2) = (s -a)

1.	The area of any cyclic quadrilateral ABCD is given by `A^(2) = (s -a) (s-b) (s-c) (s-d)`, where `2s = a + b ++ c + d, a, b, c and d` are the sides of the quadrilateral Now consider a cyclic quadrilateral ABCD of area 1 sq. unit and answer the following question The minium perimeter of the quadrilateral isA. 4B. 2C. 1D. none of these
Answer» Correct Answer - A Using A.M. `ge` G.M for `s -a, s-b, s-c, s-d`, we have `(s-a + s-b + s-c + s-d)/(4) ge sqrtA` or `(4s -2s)/(4) ge 1` or `2s ge 4`

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