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The area of cross section of a current carrying conductor is A_(0) and (A_(0))/(4) at section (1) and (2) respectively. If v_(alpha_(1)),v_(alpha_(2)) and E_(1), E_(2) be the drift velocity and electric field at sections 1 and 2 respectively then : |
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Answer» `v_(alpha_(1)):v_(alpha_(2))=1:4` |
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