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The area of cross section of a steel wire is 0.1cm2. What is the force required to double it's length ifY = 2 xx 10^11 N /M^2? |
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Answer» Solution :strain `l/L` = `THEREFOR` F = AT = `0.1 XX 10^(-4) xx 2 xx 10^11 = 2 xx 10^6 N` |
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