1.

The area of cross section of a steel wire is 0.1cm2. What is the force required to double it's length ifY = 2 xx 10^11 N /M^2?

Answer»

Solution :strain `l/L` = `THEREFOR` F = AT
= `0.1 XX 10^(-4) xx 2 xx 10^11 = 2 xx 10^6 N`


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