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The area of the coil in a moving coil galvanometer is 16 cm^2 and has 20 turns. The magnetic induction is 0.2 T ad the couple per unit twist of the suspend wire is 10^(-6) Nm per degree. If the deflection is 45^@ calculate the current passing through it. |
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Answer» SOLUTION :Given, `A = 16 cm^2 = 16 xx 10^(-4)m^2` `B = 0.2 T, N = 20, C = 10^(-6) N`m/degree ` theta = 45^@` From `C theta = BiAN` `= i (C theta)/(BAN)= (10^(-6) xx 45)/(0.2 xx 16 xx 10^(-4) xx 20) = 7 xx 10^(-3) A.` |
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