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The area of the coil in a moving coil galvanometer is 16 cm^(2) and has 20 turns. The magnetic induction is 0.2T and the couple per unit twist of the suspended wire is 10^(-6) Nm per degree. If the deflection is 45° calculate the current passing through it. |
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Answer» Solution :Given, A=`16CM^(2)=16xx10^(-4)m^(2)` `B=0.2T,N=20,C=10^(-6)Nm//`DEGREE, `theta=45^(@)` From, `Ctheta=BiAN` `i=(Ctheta)/("BAN")=(10^(-6)xx45)/(0.2xx16xx10^(-4)xx20)=7.03xx10^(-3)` |
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