1.

The area of the plates of a capacitor is 50cm^(2) each and the separation between them is 1mm. The space between the plates is filled with a material of dielectric constant 4. the capacitor, initially uncharged, is connected to a battery of EMF 50 V. the work done by the battery until the capacitor gets completely charged is (in muJ).

Answer»

0.22
0.44
0.88
1.76

Solution :Capacitance, `C=(Kepsi_(0)A)/(d)=((4)((80)/(9)xx10^(-12))(50xx10^(-4)))/(10^(-3))=(16)/(9)xx10^(-10)F`
Work DONE by the BATTERY, `W=CV^(2)=((16)/(9)xx10^(-10))(50)^(2)=0.44muJ`.


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