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The arithmetic mean of `""^(n)C_(0),""^(n)C_(1),""^(n)C_(2), ..., ""^(n)C_(n)`, isA. `(1)/(n)`B. `(2^(n))/(n)`C. `(2^(n-1))/(n)`D. `(2^(n+1))/(n)` |
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Answer» Correct Answer - B Clearly, Required mean `=(""^(n)C_(0)+""^(n)C_(1)+ ... +""^(n)C_(n))/(n) =(2^(n))/(n)` |
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