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The arithmetic mean of the series `1 , 3, 3^(2) , …., 3^(n-1)` is `"_______"`.A. `(3^(n))/(2n)`B. `(3^(n) - 1)/(2n)`C. `(3^(n-1))/(n + 1)`D. `(3^(n) + 1)/(2n)` |
Answer» Correct Answer - b `barx = (1 + 3 + 3^(2) + …+ 3^(n-1))/(n)` `= (1((3^(n) - 1)/(3-1)))/(n) = (3^(n) -1)/(2n)` |
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