

InterviewSolution
Saved Bookmarks
1. |
The armature of a `DC` motor has `20Omega` resistance. It draws a current of `1.5 A` when run by `200 V DC` supply The value of back emf induced in it will beA. 150 VB. 170 VC. 180 VD. 190V |
Answer» Correct Answer - D For DC motor, `I=(V_(S) - V_(B))/R` and `V_(B) propto omega` `1.5 = (220-V_(R))/(20) rArr V_(B) = 190 V` |
|