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The arthmetic mean of the numbers `1,3,3^(2), … ,3^(n-1),` isA. `(3^(n)-1)/(2)`B. `(3^(n)-1)/(2n)`C. `(3^(n)+1)/(2)`D. `(3^(n)+1)/(2n)` |
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Answer» Correct Answer - B Let M be the required mean. Then, `M=(1+3+3^(2)+ ... +3^(n-1))/(n)` `rArr M=(1xx((3^(n)-1)/(3-1)))/(n)=(3^(n)-1)/(2n)` |
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