1.

The atomic mass of natural boron is 10.811. It consists of two isotopes with masses of 10.013 and 11.009. Find their fractions.

Answer»


Solution :SOLVE the system of two equations:
`10.013x+11.009y=10.811,X+y=1` where x and y are the FRACTIONS of the LIGHT and the heavy isotopes, respectively.


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