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The atomic masses of Li, He and proton are 7.01823 amu, 4.00387 amu and 1.00715 amu respectively. Calculate the energy evolved in the reaction, 3^(Li^(7)) + 1^(H^(1)) rarr 2 2^(He^(4)) + triangle E Given 1 amu = 931 MeV. |
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Answer» SOLUTION :Mass of reactants = mass of LI + mass of H =7.01823 + 1.00715 =8.02358 amu mass loss during change=(8.02538 -8.00774) amu =0.01764 amu `therefore` energy evolvedduringreaction =0.0176 x 931 MEV =16.423 MeV |
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