1.

The atomic number of cerium (Ce) is 58. The correct electronicconfiguration of Ce^(3+) ion is

Answer»

`[Xe]4f^(1)`
`[Kr]4f^(-1)`
`[Xe]4f^(-13)`
`[Kr]4d^(1)`

Solution :
For Z = 56, it will be `[Xe]6s^(2)`
In LANTHANUM (Z = 57), electrons should enter in 4f but to maintain stable xenon core it will go into 5d(DIFFERENCE is little in between 4f and 5d.)
But in cerium (Ce, Z = 58), ELECTRON enters into 4f.
`therefore""Ce^(3+)=[Xe]4f^(1)`


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