1.

The atomic weight of Al is 27. When a current of 5 Faradays is passed through a solution of Al^(++) ions, the weight of al deposited is

Answer»

27gm
36gm
45gm
39gm

Solution :`Al^(3+)+3E^(-)toAl`
`E_(Al)=(27)/(3)=9`
`W_(Al)=E_(Al)XX"No. of FARADAYS"=9xx5=45gm`.


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