1.

The atomicnumber of cerium (Ce) is 58. The correct electronic configuration of Ce^(3+) ion is

Answer»

`[Xe]4F^(1)`
`[Kr]4f^(1)`
`[Xe]4f^(13)`
`[Kr]4d^(1)`

Solution :`Z = 54` is `[Xe]=Z= 56` is `BA = [ Xe] 6s^(2)`
`Z =57` ( La) is `[Xe]5d^(1)`( electron 5d in place of expected 4f)
But in `Z= 58` ( Ce ) , electron enters 4f and `5d^(1)` also shifts to 4f. Hence, electronic configuration of `Ce( 58) ` is `[Xe] 4f^(2) 5d^(0) 6s^(2)`.
`:. Ce^(3+) = [Xe]4f^(1)`


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