1.

The average emf induced in a coil in which the current changes from 2 A to 4 A in 0.05 s is 8 V. Self-inductance of the coil is

Answer»

0.1 H
0.2H
0.4H
0.8H

Solution :`|epsi|=L ""(d I)/(dt)=L ((I_(2)-I_(1))/(t)) THEREFORE L=(|epsi|t)/((I_(2)-I_(1)))= (8 XX 0.05)/((4-2))=0.2H`


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