1.

The average energy of molecules in a sample of oxygen gas at 300K are 6.2 J xx 10^(-21) J. The corresponding values at 600K are

Answer»

`12.12xx10^(-21)J`
`8.78xx10^(-21)J`
`6.21xx10^(-21)J`
`12.42xx10^(-21)J`

Solution :The AVERAGE energy of the molecule is E`=3/2KT`
`(E_(2))/(E_(1))=(T_(2))/(T_(1))=600/300=2`
`E_(2)=2E_(1)=2xx3/2KT`
`=3xx1.38xx10^(-23)xx300`
`=12.42xx10^(-21)J`
So CORRECT choice is (d).


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