1.

The average energy of molecules in a sample of oxygen gas at 300K are 6.21 xx 10^(-21)J. The corresponding values at 600K are:

Answer»

`12.12xx10^(-21)J`
`8.78xx10^(-21)J`
`6.21xx10^(-21)J`
`12.42xx10^(-21)J`

Solution :`(E.)/(E)=((2)/(3)KT.)/((3)/(2)kT)=(600)/(300)`
`THEREFORE E.=2E=12.42 xx10^(-21) J`


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