The average K.E. of an ideal gas in calories per mole is approximately – InterviewSolution

1.	The average K.E. of an ideal gas in calories per mole is approximately equal to
Answer» Three times the absolute temperature Absolutetemperature Two times the absolute temperature 1.5 times the absolute temperature Solution :`K.E. = (3)/(2). RT = (3)/(2).2.T "":'R ~=2 CALK^(-1)mol^(-1)`

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