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The average kinetic energy of an ideal gas per molecule in SI units at `25^(@)C` will beA. `6.17xx 10^(-21)Kj`B. `6.17 xx 10^(-21) J`C. `6.17 xx 10^(-20) J`D. `6.17 xx 10^(-20) J` |
Answer» Correct Answer - B Average kinetic energy per molecule. `bar(K.E.) =(3)/(2) KT = (3)/(2) xx (8.314)/(6.02 xx 10^(23))xx298` `= 6.17 xx 10^(-21) J` |
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