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The average life time of an excited state of an electron in Hydrogen is of order of `10^(-8)s. It makes (xxx10^(6))` revolutions when it is in the state `n=2` and before it suffers a transition `n=1` state. Find the value of `xx` . Given `h/(4pi^(2)ma_(-0)^(2))=64xx10^(14)`, where m is mass of electron and `a_(0)` is Bohrs radius .

Answer» `r=(mv)/(Bq)=p/(Bq)RightarrowP=Bqr and lambda=h/p` i.e `lambda_(1)/lambda_(2)=P_(2)/p_(1)=(Bq_(2)r)/(Bq_(1)r)=q_(2)/q_(1)=2/1=2`


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