1.

The Average Of The First 100 Positive Integers Is?

Answer»

N(n+1)/2

1+2+3+....+n

THEREFORE AVERAGE of these numbers=n+1/2

therefore REQUIRED average

100+1/2=50.5

n(n+1)/2

1+2+3+....+n

therefore average of these numbers=n+1/2

therefore required average

100+1/2=50.5



Discussion

No Comment Found