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What Is The Probability Of Getting A Sum 9 From Two Throws Of A Dice? |
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Answer» In two throws of a dice, N(S) = (6 X 6) = 36. Let E = EVENT of GETTING a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}. P(E) = n(E)/ n(S)=4/36 =1/9. In two throws of a dice, n(S) = (6 x 6) = 36. Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}. P(E) = n(E)/ n(S)=4/36 =1/9. |
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