1.

What Is The Probability Of Getting A Sum 9 From Two Throws Of A Dice?

Answer»

In two throws of a dice, N(S) = (6 X 6) = 36.

Let E = EVENT of GETTING a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) = n(E)/ n(S)=4/36 =1/9.

In two throws of a dice, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) = n(E)/ n(S)=4/36 =1/9.



Discussion

No Comment Found