1.

The average oxidation state of sulphur atom inS0 ion is

Answer»

+2.5 (No, this isn't an anomaly. Let me explain first)

Explanation:

First we need to calculate the oxidation state of S atom the usual way

S4O6(2-)

overall oxidation state = -2

[oxidation state of S x 4] +[oxidation state of O atom x 6]=-2

The oxidation state of oxygen is -2.

[oxidation state of S x 4]+[(-2)(6)] =-2

Let y be the oxidation state of S

Therefore, we can rewrite the equation as

[(y ) (4)] + [(-2) (6)] = -2

[(y ) (4)] + (-12) = -2

[(y ) (4)] = -2 + (+12)

[(y )(4)] = +10

y = +10/4

y = + 2.5


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