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The average speed at temperature `T^(@)C` of `CH_(4)(g)` is `sqrt((28)/(88))xx10^(3)ms^(-1)`. What is the value of T ?A. `240.55^(@)C`B. `-32.45^(@)C`C. `3000^(@)C`D. `-24.055^(@)C` |
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Answer» Correct Answer - b (b) `sqrt((8RT)/(piM))=sqrt((28)/(88))=sqrt((7)/(22))` `(8xx8.314xxT)/(pixx16xx10^(-3))=(7)/(22)xx10^(6)` `T=(1000xx2)/(8.314)=240.55K` `T^(@)C=240.55-273=-32.45^(@)C` |
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