The average speed of air molecules is `485 "ms"^(-1)` . At STP the number density is `2.7xx10^(25)m^(-3)` and diameter of the air molecule is `2xx10^(-10)` m . The value of mean free path for the air molecule isA. `2.5xx10^(-7)m`B. `2.9xx10^(-7)m`C. `3.5xx10^(-7)m`D. `3.9xx10^(-7)m`

The average speed of air molecules is `485 "ms"^(-1)` . At STP the num

1.	The average speed of air molecules is `485 "ms"^(-1)` . At STP the number density is `2.7xx10^(25)m^(-3)` and diameter of the air molecule is `2xx10^(-10)` m . The value of mean free path for the air molecule isA. `2.5xx10^(-7)m`B. `2.9xx10^(-7)m`C. `3.5xx10^(-7)m`D. `3.9xx10^(-7)m`
Answer» Correct Answer - B Given , number density of the air molecule, `n=2.7xx10^(25)//m^(3)` diameter of the air molecule, `d=2xx10^(-10)m` mean free path , `lambda` = ? we know that , mean free path, `lambda=(1)/(sqrt2npid^(2))=(1)/(sqrt2pixx2.7xx10^(25)(2xx10^(-10))^(2))=2.9xx10^(-7)m`

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The average speed of air molecules is `485 "ms"^(-1)` . At STP the number density is `2.7xx10^(25)m^(-3)` and diameter of the air molecule is `2xx10^(-10)` m . The value of mean free path for the air molecule isA. `2.5xx10^(-7)m`B. `2.9xx10^(-7)m`C. `3.5xx10^(-7)m`D. `3.9xx10^(-7)m`

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