1.

The average translational energy and the r.m.s. speed of molecules of a sample of oxygen gas at 300 K" are "6 cdot 21 xx 10^(-21)J and 484 ms^(-1) respectively. The corresponding values at 600 K are nearly (assuming ideal gas behaviour) :

Answer»

`8 cdot 78xx10^(-21) J, 684 ms^(-1)`
`6 cdot 21 xx10^(-21)J, 968 ms^(-1)`
`12 cdot 42 xx10^(-21) J, 968 ms^(-1)`
`12 cdot 42 xx10^(-21) J, 968 ms^(-1)`

Solution :`K.E. prop` temperature
`THEREFORE (E_(2))/(E_(1))=(T_(2))/(T_(1)) rArr E_(2)=2E_(1)=12 cdot 42 xx10^(-21) J`
And `v_(rms) prop SQRT(T)`
`(v_(2))/(v_(1))=sqrt((T_(2))/(T_(1)))`
`rArr v_(2)=v_(1) sqrt((600)/(300)) =1 cdot 414 xx 484 =684 ms^(-1)`
Thus, CORRECT choice is (c).


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