1.

The average translational kinetic energy of air molecules is `0.040 eV (1eV=1.6xx10^(-19)J).` Calculate the temperature of the air. Blozmann constant `K=1.38xx10^(-23) J K^(-1).`

Answer» Average K.E.= 3/2
`(3/2 KT) = (0.04 xx 1.6 xx 10^-19 )`
` rArr (3/2 xx 1.38 xx 10^-23 xx T)`
=0.04 xx 1.6 xx 10^-19`
`rArr T= (2 xx 0.04 xx 1.6 xx 10^-19)/(3 xx 1.38 xx 10^-23)`
` =0.0309178 xx 10^4`
` =309.178 =310K`


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