1.

The average translational kinetic energy of nitrogen gas molecules is 0.02 eV(1 eV = 1.6xx10^(-19)J). Calculate the temperature of the gas. Boltzmann constant k=1.38xx10^(-28)J//K.

Answer»

193.1 K
1011 K
212 K
154.5 K

SOLUTION :Translational K.E. of nitrogen molecule = `(3)/(2)kT`
`(3)/(2)kT=0.02eV=0.02xx1.6xx10^(-19)J`
`T=(0.02xx1.6xx10^(-19))/(1.38xx10^(-23))xx(2)/(3)orT=154.5K`


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