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The average value of a saw-tooth voltage `V=V_(0) ((2t)/(T)-1)` Over 0 to `(T)/(2)`, (T- time period) is given byA. `(V_(0))/(sqrt(2))`B. `(2V_(0))/(pi)`C. `(V_(0))/(2)`D. `V_(0)` |
Answer» Correct Answer - C | |