The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega )` to `t=(3 pi)/(2 omega)` si how many times of `(I_m)`?

The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega

1.	The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega )` to `t=(3 pi)/(2 omega)` si how many times of `(I_m)`?
Answer» `ltIgt =(underset(0)overset((2pi)/(omega))int sin omegatdt)/((2pi)/(omega))=((I_(m))/(omega)(1-cos omega(2pi)/(omega)))/((pi)/(omega))=(2I_(m))/(pi) ` (ii) `ltIgt =(underset((pi)/(2omega))overset((2pi)/(omega))int I_(m) sin omegatdt)/((pi)/(omega))=0`

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The average value of current `i=I_(m) sin omega t from t=(pi)/(2 omega )` to `t=(3 pi)/(2 omega)` si how many times of `(I_m)`?

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