1.

The average velocity of CO_(2) at T_(1) K and most probable velocity at T_(2)K is 9 × 10^(4) cm//s. Calculate the values of temperatures, T_(1) and T_(2)K.

Answer»

Solution :Average VELOCITY of `CO_(2)` at `T_(1) K = sqrt((8RT_(1))/(π M))`
`implies 9 xx 10^(2) m//sec= sqrt((8RT_(1))/(π (44 xx 10^(-3))))= sqrt(( 8 xx 8.314 xx T_(1))/(3.14(44 xx 10^(-3))))implies T_(1)=1682.5K`
SIMILARLY, Most probable velocity of `CO_(2)` at `T_(2)K = sqrt((2RT_(2))/(M))`
`implies 9 xx 10^(2) m//s= sqrt((2 xx 8.314 xx T_(2))/(44 xx 10^(-3)))implies T_(2)= 2143.37K`


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