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The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will beA. 0.6 `m//` secB. `0.3 m//` secC. `0.9 m // `secD. `3.0 m //` sec |
Answer» Correct Answer - A `U_(av) =sqrt((8RT)/(piM)),{(T_(1)= 27+273=300K),(T_(2)=927+273=1200K):}}` `(U_(av_(1)))/(U_(av_(2)))=sqrt((T_(1))/(T_(2)))` or `(0.3)/(U_(av_(2)))=sqrt((300)/(1200))`or `(0.3)/(U_(av_(2)))=sqrt((1)/(4))` or `U_(av_(2))=0.6 m//`sec |
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