1.

The bacterial growth follows the rate law,(dN)/(dt)=kN, where k is a constant and N is the number of bacterial cell at any time. If the population of bacteria (no. of cell) is doubled in 5 minutes then the time by which the population will be eight times of the initial one.

Answer»

15 mins
10 mins
12 mins
18 mins

SOLUTION : We know that, `(dN)/(DT)`=kN `impliesN=N_0^(e^(KT))`
In 5 min `impliesN=2N_0`
`k=(2.303)/(t)log (N)/(N_0) = (2.303)/(5) log (2N_0)/(N_0)`
`=(2.303)/(5) log 2`= 0.138
For 8 `N_0,t=(2.303)/(0.138) log (8N_0)/(N_0)`=15 min


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