The base of a isosceles triangle is 4/3cm.The perimeter of the triangl

1.	The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides?koi hai ???
Answer» Answer: LET any of the remaining SIDE of the isosceles triangle is X cm in LENGTH. Then, Perimeter of triangle, =x+x+43=2x+43 cm ⇒2x+43=4215( Perimeter is 4215) ⇒2x+43=6215⇒2x=6215−43 ⇒2x=4215⇒x=1410=75=125 cm So, Required sides of given triangles are 125 cm each.

The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides?koi hai ???

Answer»

Answer:

LET any of the remaining SIDE of the isosceles triangle is X cm in LENGTH. Then,

Perimeter of triangle, =x+x+43=2x+43 cm

⇒2x+43=4215( Perimeter is 4215)

⇒2x+43=6215⇒2x=6215−43

⇒2x=4215⇒x=1410=75=125 cm

So, Required sides of given triangles are 125 cm each.

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The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides?koi hai ???​

LET any of the remaining SIDE of the isosceles triangle is X cm in LENGTH. Then,

Perimeter of triangle, =x+x+43=2x+43 cm

⇒2x+43=4215( Perimeter is 4215)

⇒2x+43=6215⇒2x=6215−43

⇒2x=4215⇒x=1410=75=125 cm

So, Required sides of given triangles are 125 cm each.

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The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides?koi hai ???