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The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides? |
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Answer» 7/5cm is the REQUIRED length of remaining sides .Step-by-step explanation:According to the QuestionIt is given that ,Base of isosceles triangle = 4/3 cmPerimeter of triangle = 64/15 cmWe have to calculate the length of remaining equal sides .As we know that TWO sides in Isosceles triangle are equal in length .LET the equal length of triangle be x cmNow, PERIMETER of triangle = Sum of length of all sidesPutting the VALUES we get➻ x + x + 4/3 = 62/15 ➻ 2x + 4/3 = 62/15➻ 2x = 62/15 - 4/3➻ 2x = 62-20/15➻ 2x = 42/15➻ x = 42/30 cm➻ x = 14/10➻ x = 7/5Hence, the length of remaining equal sides of triangle will be 7/5cm . |
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