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| 1. |
The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. Find its area. |
| Answer» LET the congruent sides of the isosceles triangle = a and the base = bGiven, b = 12cmPerimeter of the triangle = sum of all sides =a+a+b = 322a+ 12 = 32On solving, a = 10cmSince the height of the triangle, divides it into two RIGHT angled triangles,a^2 = h^2 +(b/2)^2 = 10^2 =h^2+6^2h^2 = 100 - 36 = 64h = root 64 = 8 CMAREA of triangle = 1/2 × base × height =1/2 ×12×8 = 48 sq cm | |