1.

The base of an isosceles triangle is 12 cmand its perimeter is 32 cm. Find its area.

Answer» Let the length of the two equal sides be x.
Perimeter of triangle=`32=2x+12`
=>`x=10`
Area of triangle=`sqrt(s(s-a)(s-b)(s-c))` where s is the semiperimeter of triangle
`s=32/2=16`
`sqrt(16xx6xx6xx4)=4 xx 6xx 2=48(cm)^2`


Discussion

No Comment Found