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The base of an isosceles triangle is 12 cmand its perimeter is 32 cm. Find its area. |
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Answer» Let the length of the two equal sides be x. Perimeter of triangle=`32=2x+12` =>`x=10` Area of triangle=`sqrt(s(s-a)(s-b)(s-c))` where s is the semiperimeter of triangle `s=32/2=16` `sqrt(16xx6xx6xx4)=4 xx 6xx 2=48(cm)^2` |
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