1.

The best reagent for converting 2-phenylpropanamide into 2-phenylpropanamine is_____.

Answer»

excess `H_(2)`
`Br_(2)` in aqueous NaOH
iodine in the presence of RED phosphorus
`LiAlH_(4)` in ether

Solution :`UNDERSET("2-Phenylpropanamide")(C_(6)H_(5)-OVERSET(CH_(3))overset(|)(C)H-CONH_(2) overset(LiAlH_(4)//Ether)to underset("2-Phenylpropanamine")(C_(6)H_(5)-overset(CH_(3))overset(|)(C)H-CH_(2)NH_(2))`


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